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2x^2+60x-1=0
a = 2; b = 60; c = -1;
Δ = b2-4ac
Δ = 602-4·2·(-1)
Δ = 3608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3608}=\sqrt{4*902}=\sqrt{4}*\sqrt{902}=2\sqrt{902}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{902}}{2*2}=\frac{-60-2\sqrt{902}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{902}}{2*2}=\frac{-60+2\sqrt{902}}{4} $
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